/*
 * Author  : Amit Dutta <amitdutta4255@gmail.com>
 * Date    : 08 Feb 2026
 * Repo    : https://github.com/notamitgamer/bsc
 * License : MIT License (See the LICENSE file for details)
 */

/* Given an array p[5], write a function to shift it circularly left by two positions. Call this function for a 4 x 5 matrix and get its rows left shifted.
*/

/* Let Us C, Chap- 14 (Multidimensional Arrays), Qn No.: C(h) */

/* This file is auto-generated by a bot. */
/* This code is not compiled; it is for reference only. */


#include <stdio.h>
#include <stdlib.h>

void shift_left_two(int *p, int n);
void print_row(int *p, int n);

int main()
{
    int mat[4][5] = {
        {15, 30, 28, 19, 61},
        {1, 2, 3, 4, 5},
        {10, 20, 30, 40, 50},
        {5, 4, 3, 2, 1}
    };
    int i;

    printf("Original Matrix:\n");
    for (i = 0; i < 4; i++)
        print_row(mat[i], 5);

    // Apply shift to each row
    for (i = 0; i < 4; i++)
    {
        shift_left_two(mat[i], 5);
    }

    printf("\nMatrix after shifting each row left by 2:\n");
    for (i = 0; i < 4; i++)
        print_row(mat[i], 5);

    return 0;
}

void shift_left_two(int *p, int n)
{
    if (n < 2) return; // Cannot shift if less than 2 elements

    int temp1 = p[0];
    int temp2 = p[1];
    int i;

    // Shift elements left by 2
    for (i = 0; i < n - 2; i++)
    {
        p[i] = p[i + 2];
    }

    // Place the first two elements at the end
    p[n - 2] = temp1;
    p[n - 1] = temp2;
}

void print_row(int *p, int n)
{
    int i;
    for (i = 0; i < n; i++)
    {
        printf("%d ", p[i]);
    }
    printf("\n");
}