/* * Author : Amit Dutta * Date : 12 Dec 2025 * Repo : https://github.com/notamitgamer/bsc * License : MIT License (See the LICENSE file for details) */ /* In digital world colors are specified in Red-Green-Blue (RGB) format, with values of R, G, B varying on an integer scale from 0 to 255. In print publishing the colors are mentioned in Cyan-Magenta-Yellow-Black (CMYK) format, with values of C, M, Y, and K varying on a real scale from 0.0 to 1.0. Write a program that converts RGB color to CMYK color as per the following formulae: White = Max(Red/255, Green/255, Blue/255) Cyan = (White-Red/255) / White Magenta = (White-Green/255) / White Yellow = (White-Blue/255) / White Black = 1 - White Note that if the RGB values are all 0, then the CMY values are all 0 and the K value is 1. */ /* Let Us C, Chap- 4, Page - 71, Qn No.: D(b) */ #include // declaring function double get_white(double red, double green, double blue) { double max; max = red / 255; if (max < (green / 255)) max = green / 255; if (max < (blue / 255)) max = blue / 255; return max; } int main() { double r, g, b, w, c = 0, m = 0, y = 0, k = 0; printf("Enter the RGB color code in 'R G B' format : "); scanf("%lf %lf %lf", &r, &g, &b); // checking for invalid input (negetive input) if (r < 0 || g < 0 || b < 0) { printf("\nRGB color code can not be a negetive number."); return 1; } // checking for invalid input (out of range color code) if (r > 255 || g > 255 || b > 255) { printf("\nRGB color code can be maximum (255, 255, 255)."); return 1; } // converting RGB color code to CMYK color code if (r == 0 && g == 0 && b == 0) k = 1; else { w = get_white(r, g, b); c = (w - (r / 255)) / w; m = (w - (g / 255)) / w; y = (w - (b / 255)) / w; k = 1 - w; } printf("\nRGB color (%g, %g, %g) equivalent to CMYK color (%g, %g, %g, %g).", r, g, b, c, m, y, k); return 0; }